log (x/y)= x+y find dy/dx
architaa:
as per i know log(x/y) = log x –log y and not log x + log y.
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log dy/dx
log dy – log dx {log(x/y)=logx–logy}
log d + log y –(log d + log y){log(xy)=logx+logy}
log d + log y – log d – log y
log dy – log dx {log(x/y)=logx–logy}
log d + log y –(log d + log y){log(xy)=logx+logy}
log d + log y – log d – log y
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