Question

log (x²-1)- log(x+1)= -log 9 then x =
please answer it its urgent ​

Answer 1

Refer the picture, hope this helps

Answer 2

$log( {x}^{2} - 1) - log(x + 1) = - log(9) \\ \\ log( \frac{ {x}^{2} - 1}{x + 1} ) = - log(9) \\ \\ log( \frac{(x + 1)(x - 1)}{x + 1} ) = - log(9) \\ \\ log(x - 1) = - log(9) \\ \\ log(x - 1) = log( \frac{1}{9} ) \\ \\ x - 1 = \frac{1}{9} \\ \\ x = \frac{1}{9} + 1 \\ \\ x = \frac{1 + 9}{9} \\ \\ x = \frac{10}{9}$

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