Question

Log(x2+5x+4) /2logx=1

Answer 1

Step-by-step explanation:

For x>1 we have that. log(x− 1)+log(x+1)=log(x+2)2. log(x2−1)=log(x+2)2. x2−1=(x+2)2. x2−1=x2+4x+4. x=−54.

For x>1 we have that log(x−1)+log(x+1)=log(x+2)2 log(x2−1)=log(x+2)2 x2−1=(x+2)2 x2−1=x2+4x+4 x=−54 However this solution is not acceptable

Answer 2

Answer:

log x^2 + 5x + 4

_______________ = 1

2logx

log x^2 + 5x + 4

_________________ = 1

logX^2

x^2 + 5x + 4

_______________ = 1

x^2

x^2 + 5x - 4 = x^2

5x - 4 = 0

5x = 4

x = 4/5,,

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