log(x2-6x+7)=log(x-3) then x=?
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Answer:
log(x2-6x+7)=log(x-3)
x2-6x+7=x-3
x2-7x+10=0
x2-2x-5x+10=0
x(x-2)-5(x-2)=0
(x-5)(x-2)=0
x=5 or 2
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