Question

Log(x²-8x) to the base 3 is equal to 2



Find x

Pls explain with method

Answer 1

$HEYA \: \\ \\ GIVEN \: \: QUESTION \: \: Is \: \: \\ \\ log_{3}(x {}^{2} - 8x) = 2 \\ \\ (x {}^{2} - 8x) = 3 {}^{2} \\ becoz \: \: if \: \: \: log_{y}(z) = m \: \: \: then \: \: z = y {}^{m} \\ \\ x {}^{2} - 8x - 9 = 0 \\ \\ x {}^{2} - 9x + 1x - 9 = 0 \\ \\ x(x - 9) + 1(x - 9) = 0 \\ \\ (x + 1) = 0 \: \: \: or \: \: \: (x - 9) = 0 \\ \\ x = - 1 \: \: \: or \: \: \: x = 9$

Answer 2

Step-by-step explanation:

$\begin{lgathered}HEYA \: \\ \\ GIVEN \: \: QUESTION \: \: Is \: \: \\ \\ log_{3}(x {}^{2} - 8x) = 2 \\ \\ (x {}^{2} - 8x) = 3 {}^{2} \\ becoz \: \: if \: \: \: log_{y}(z) = m \: \: \: then \: \: z = y {}^{m} \\ \\ x {}^{2} - 8x - 9 = 0 \\ \\ x {}^{2} - 9x + 1x - 9 = 0 \\ \\ x(x - 9) + 1(x - 9) = 0 \\ \\ (x + 1) = 0 \: \: \: or \: \: \: (x - 9) = 0 \\ \\ x = - 1 \: \: \: or \: \: \: x = 9\end{lgathered}$