Question

(Log X²) - log(log x) = log2

Answer 1

Answer:

log(x^2+4)=2+ log(x)−log(20)

log(x^2+4)=2 + log(x/20) [loga - logb =loga/b]

log(x^2+4) - log(x/20)=2

log[(x^2+4)*20/x] =2 [loga - logb =loga/b]

log[(x^2+4)*20/x] =log100 [2=log100]

(x^2+4)*20/x =100 [Dividing by 20 both sides]

(x^2+4)*1/x =5

Cross Multiply

x^2+4 =5x

x^2-5x+4 =0

x^2-4x-x+4 =0

(x-4)(x-1) =0

So x=4,1