Question

Log xy^3=m and log x^3y^2=p,find log ( x^2÷ y) in terms of m and p

Answer 1

log (x²/y) = p - m

Step-by-step explanation:

Given,

log (x y³) = m ..... (1)

log (x³ y²) = p ..... (2)

We have to find log (x²/y) in terms of m and p.

Now, log (x²/y)

= log {(x³ y²)/(x y³)}

= log (x³ y²) - log (x y³)

= p - m

i.e., log (x²/y) = p - m, in terms of p and m

This is the required value.

Rules for logarithmic operations:

1. log (ab) = loga + logb

2. log (a/b) = loga - logb

3. log (aᵇ) = b loga

Answer 2

HELLO GUYS

THE ABOVE ANSWER IS CERTAINLY CORRECT BUT NOT TOO UNDERSTANDABLE

SO I AM GIVING U THE DETAILED ANSWER OF THIS QUESTION THAT IS VERY EASY TO UNDERSTAND

log xy^3 = m -----(1)

log x^3y^2 = p ------(2)

NOW JUST DIVIDE (2) IN RESPECT OF (1)

WE GET =

log x^3y^2/log xy^3 = p/m. [SIMPLE]

NOW SOLVING IT WE GET

log x^3-1 y^2-3 = p - m

log x^2 y^-1 = p - m

NOW PUT Y DOWN

logx^2/y = p - m

VERIFIED ANSWER ✓✓ BY PRIYANSHU THE GREAT MATHEMATICAN LOVER OF METHODIST HIGH SCHOOL

"MATHS IS DIFFICULT FOR THOSE WHO NEVER TRIED TO UNDERSTAND IT"

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