Log xy = log x/y + 2 log 2 = 2
x > 0 and y > 0
Find x and y
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2
Answer:
Step-by-step explanation:
log xy= log x/y +2 log 2 = 2
taking the first two;
log xy= lof x/y +2 log 2
⇒ log x + log y = log x - log y + 2 log 2
⇒ log y = -log y + 2 log 2
⇒ 2 log y = 2 log 2
⇒ y = 2
taking first and third;
log xy = 2
⇒ log 2x = 2
⇒ 2x = 10² = 100
⇒ x = 100/2 = 50
x = 50, y = 2
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Answer: x = 50
Step-by-step explanation:log x + log y = 2
log x - log y + 2 log 2 = 2
2 log y - 2 log 2 = 0
y = 2
log 2x = 2
2x = 100
x = 50
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