Math, asked by hanviammu9, 2 months ago

log1/32 base ✓2
log1by32 \: base \sqrt{2}

Answers

Answered by Anonymous
6

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 \dashrightarrow \sf log_{ \sqrt{2} }( \frac{1}{32} )  =  {?}^{}

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{ \huge{ \star}} \:  \:  \:  \:  \underline{\bf \LARGE{Solution : }}

 \:  \:  \:  \:  \:  \circ \:  \:  \:  \:  \: \sf log_{ \sqrt{2} }( \frac{1}{32} )    {}^{}

 \sf \implies \: log_{ \sqrt {2}}( {2})  {}^{ - 5}

 \sf \implies \: log_{ \sqrt {2} }( 2) {}^   { -  \frac{10} {2}}

 \implies \sf \:  log_{ \sqrt{2} }( \sqrt{2} )  {}^{ - 10}

 \implies \sf { - 10}  \:  log_{ \sqrt{2} }( \sqrt{2} )

 \:  \:  \:  \:  \:  \:  \:  \:  \therefore \underline{ \boxed{ \sf{ \:  - 10 \: }}}

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{ \huge{ \star}} \:  \:  \:  \:  \underline{\bf \LARGE{Formula  \:  \: Required : }}

 \dashrightarrow \sf \:  log_{a}(a)  = 1

 \sf \dashrightarrow \:  log_{a}(x)  {}^{n}  = n \:  log_{a}(x)

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HOPE THIS IS HELPFUL...

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