Math, asked by vinaykhandal, 1 year ago

log10[log2(log4x)]= 0 then find the value of x

Answers

Answered by imphenomenal1
1
log10=1
so,
log2(log4x)=0
log2 is constant.
log4x=0
log4x=log1
4x=1
x=1/4
Answered by lovingheart
0

Answer:

The value of x is 16

Step-by-step explanation:

Given Data:

log10[log2(log4x)]= 0

We need to find the value of x.

Step 1:

In order to find value of x, we need to isolate x which can be done by converting logarithmic equation into exponential equation using formula:

Log2( a)=c => b^{c} =a.

Step 2:

In this formula, base (b) remains fixed at its position while other values a and c switch. So applying this formula on given problem, we get:

10^0=log2 (log4(x))

1= log2 (log4(x))

log2 (log4(x)) = 1.

Step 3:

Apply above formula again.

2^{1} = log4(x)

2= log4(x)

Step 4:

Apply above formula again.

4^{2}=x

16=x

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