log10 (x+3)² + log₁0x² = 2, then x =
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1
Answer:
Given,
log
10
(−x)
=log
10
(
x
2
)
log
10
(−x)
=log
10
x
log
10
(−x)=(log
10
(x))
2
log
10
(−1)+log
10
(x)=(log
10
(x))
2
let log
10
(x)=u
log
10
(−1)+u=(u)
2
log
10
(−1) is not defined
u=Undefined
log
10
(x)=Undefined:x=10
Undefined
x=10
Undefined
False
No solution for x∈R
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