Question

log10[x square-5x+7]=0 then value of x is​

Answer 1

Answer: 2,3

Step-by-step explanation:

$log_{10} (x^{2}-5x+7) = 0\\ x^{2}-5x+7 = 1\\x^{2}-5x+6 = 0\\(x-2)(x-3) = 0\\x = 2,3$

So, x = 2,3

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