Math, asked by gbaluvidya, 10 months ago

log2=0.3010,log3=0.4771,log7=0.8451 find the value of log12.6

Answers

Answered by abhisheklala2802
0

Answer:

1.100370

Step-by-step explanation:

log 12.6 = log 126/10

=log 126 - log 10

=log ( 2*3*3*7)-1

=log2 +2log3+log 7 -1

= 1.100370

put the above given values

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Answered by dhruvruhaan2619
1

Answer: 1.1003

Step-by-step explanation:

log 12.6 can be written as log 126/10

simplify: log 126- log 10

log(7×3×3×2) - 1

log 7 + log 3 + log 3 + log 2 - 1

Substitute and find answer

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