Question

log2 (10) = x; log3 (10)= y; Find log10 (60)

Answer 1

Answer:

$log_{10}60 \\ \\ = log_{10}(2) + log_{10}(3) + log_{10}(10) \\ \\ = \frac{ log_{e}(10) }{ log_{e}(2) } + \frac{ log_{e}(10) }{ log_{e}(3) } + 1 \\ \\ \frac{1}{x} + \frac{1}{y} + 1 \\ \\ \frac{x + y + xy}{xy}$