log2)^3(logx)+2(log2)(logx)+1=0 find the sum of all possible value of x
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Answer:
5log2.logx = -1
log2.logx = -1/5
logx = -1/5log2
logx = -1loge/5
x = e raise to -1loge/5
x = 2 raise to -1/5
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