Math, asked by rajinder396, 1 year ago

log2)^3(logx)+2(log2)(logx)+1=0 find the sum of all possible value of x

Answers

Answered by sonu007451
0

Answer:

5log2.logx = -1

log2.logx = -1/5

logx = -1/5log2

logx = -1loge/5

x = e raise to -1loge/5

x = 2 raise to -1/5

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