Question

log2 base x + log4 base x + log8 base x = 6 . find x ​

Answer 1

Answer:

x = 2

Step-by-step explanation:

$\sf {log}_{x}{2} + {log}_{x}{4} + log_{x}{8} = 6 \\ \\ \sf {log}_{x}{2} + {log}_{x}{{2}^{2}} + log_{x}{{2}^{3}} = 6 \\ \\ \sf {log}_{x}{2} + 2{log}_{x}{2} + 3log_{x}{2} = 6 \\ \\ \sf 6{log}_{x}{2} = 6 \\ \\ \sf {log}_{x}{2} = 1 \\ \\ \sf {x}^{1} = 2 \\ \\ \sf x = 2$

❣️NIRANJAN45❣️

Answer 2

Answer:

x = 2

Step-by-step explanation:

\begin{gathered}\sf {log}_{x}{2} + {log}_{x}{4} + log_{x}{8} = 6 \\ \\ \sf {log}_{x}{2} + {log}_{x}{{2}^{2}} + log_{x}{{2}^{3}} = 6 \\ \\ \sf {log}_{x}{2} + 2{log}_{x}{2} + 3log_{x}{2} = 6 \\ \\ \sf 6{log}_{x}{2} = 6 \\ \\ \sf {log}_{x}{2} = 1 \\ \\ \sf {x}^{1} = 2 \\ \\ \sf x = 2\end{gathered}

log

x

2+log

x

4+log

x

8=6

log

x

2+log

x

2

2

+log

x

2

3

=6

log

x

2+2log

x

2+3log

x

2=6

6log

x

2=6

log

x

2=1

x

1

=2

x=2