log2 base x + log4 base x + log8 base x = 6 . find x
Answers
Answered by
7
Answer:
x = 2
Step-by-step explanation:
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Answered by
4
Answer:
x = 2
Step-by-step explanation:
\begin{gathered}\sf {log}_{x}{2} + {log}_{x}{4} + log_{x}{8} = 6 \\ \\ \sf {log}_{x}{2} + {log}_{x}{{2}^{2}} + log_{x}{{2}^{3}} = 6 \\ \\ \sf {log}_{x}{2} + 2{log}_{x}{2} + 3log_{x}{2} = 6 \\ \\ \sf 6{log}_{x}{2} = 6 \\ \\ \sf {log}_{x}{2} = 1 \\ \\ \sf {x}^{1} = 2 \\ \\ \sf x = 2\end{gathered}
log
x
2+log
x
4+log
x
8=6
log
x
2+log
x
2
2
+log
x
2
3
=6
log
x
2+2log
x
2+3log
x
2=6
6log
x
2=6
log
x
2=1
x
1
=2
x=2
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