Log2-log4 +log6 can be written as a single logarithm
with base 10 as.........
(a) Log4
(b) log10/6
(C) Log8
(d) Log6
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Well see your answer first...
log(ab) = log(a) + log(b).....
log(a/b) = log(a) - log(b).....
So using the property...
log(2) - log(4) + log(6)
= log(2) + log(6) - log(4)
= log(2*6) - log(4)
= log(12/4) = log(3)......
As per my knowledge all options are incorrect....
Will you be my girlfriend....
See my profile....
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