log2 rational or irrational? justify your answer.
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Assume that log 2 is rational, that is,
(1)
where p, q are integers.
Since log 1 = 0 and log 10 = 1, 0 < log 2 < 1 and therefore p < q.
From (1),
, where q – p is an integer greater than 0.
Now, it can be seen that the L.H.S. is even and the R.H.S. is odd.
Hence there is contradiction and log 2 is irrational.
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