Question

log2- root 3 (2+ root 3 )=?​

Answer 1

Answer:

Ans : -1

Log 1 = 0

Since base is (2+√3)

So log (2 +√3) = 1

2 - √3 = (2-√3)×(2+√3) / (2+√3)

= 1 / (2+√3)

log 2-√3

=log 1 / (2+√3)

=log 1 - log (2+√3)

Answer 2

Step-by-step explanation:

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