Question

log2 sinx- log2 cosx- log2 (1-tanx)-lpg(1+tanx)=-1​

Answer 1

Answer:

o......,...........is the answer

Answer 2

Answer:

x=n^/2+^/8

Step-by-step explanation: log2tanx-(log2(1-tan²x]=-1

log2=tanx/1-tan²x=-1

tanx/1-tan²x=1/2

2tanx/1- tan²=1

tan2x=1

2x=nπ+π/4

x=nπ/2+π/8