log245(175)=a log1715(875)=b
find the value of 1-ab/a-b
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Given: a = log( base 245) 175 b = log( base 1715) 875
To find: The value of 1 - ab / a - b
Solution:
- Now we can write a = log( base 245) 175 as:
a = log 175 / log 245
- Also we can write b = log( base 1715) 875 as:
b = log 875 / log 1715
- Now, putting the values in 1 − ab / a − b, we get:
1 − ( log 175 / log 245 x log 875 / log 1715) / (log 175/log 245 − log 875 / log 1715)
1 − { ( log 25 + log 7 )/( log 5 + 2 log 7 ) x (log 125 + log 7)/(log 5 + 3 log 7 ) / (log 25 + log 7)/(log 5 + 2 log 7)−(log 125 + log 7)(log 5 + 3 log 7)
- which comes out to be 1
Answer:
The value of 1 - ab / a - b is 1
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0
Answer:
We can take any number as the base of the logarithm. Here 5 and 7 can be chosen.
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