Math, asked by anuveshkumars1561, 11 months ago

log245(175)=a log1715(875)=b
find the value of 1-ab/a-b

Answers

Answered by Agastya0606
7

Given: a = log( base 245) 175 b = log( base 1715) 875

To find: The value of 1 - ab / a - b

Solution:

  • Now we can write a = log( base 245) 175 as:

            a = log 175 / log 245

  • Also we can write b = log( base 1715) 875 as:

            b = log 875 / log 1715

  • Now, putting the values in 1 − ab / a − b, we get:

1 − ( log 175 / log 245 x log 875 / log 1715) / (log 175/log 245 − log 875 / log 1715)

1 − { ( log 25 + log 7 )/( log 5 + 2 log 7 ) x (log 125 + log 7)/(log 5 + 3 log 7 )  /  (log 25 + log 7)/(log 5 + 2 log 7)−(log 125 + log 7)(log 5 + 3 log 7)

  • which comes out to be 1

Answer:

          The value of 1 - ab / a - b is 1

Answered by NidhiDodiya
0

Answer:

We can take any number as the base of the logarithm. Here 5 and 7 can be chosen.

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