Question

log27=a then 3-a/3+a. find solutions​

Answer 1

log

12

27=a

log12

log27

=a

⇒3log3=a[2log2+log3]

⇒3log3−alog3=2alog2

⇒log3=

3−a

2alog2

.......(1)

Now log

6

16=

log6

log16

⇒

log2+log3

4log2

..... (2)

⇒=

log2+

3−a

2alog2

4log2

[using (1)]

⇒

3+a

4(3−a)

Hence, option A is the correct answer