Question

log28/51-log70/69+log85/46=0​

Answer 1

Concept:

$logab=logaelogb\\log\frac{a}{b}=loga-logb$

Given:

$log\frac{28}{51} -log\frac{70}{69} +log\frac{85}{46} =0$

To find:

The value of the log

Solution:

In this question, a log function is given to us, which is $log\frac{28}{51} -log\frac{70}{69} +log\frac{85}{46} =0$

So, we know two properties of log that is

$logab=logaelogb\\log\frac{a}{b}=loga-logb$

Now if we would put the values of a and b in the formula then we can get the value of the log

so, we get $log\frac{\frac{28}{51}\frac{85}{46} }{\frac{70}{69} }$

here, we have taken the positive log functions in the numerator and the negative log functions in the denominator

$log\frac{\frac{28}{51}\frac{85}{46} }{\frac{70}{69} }\\log(\frac{28}{51}*\frac{85}{46}*\frac{69}{70} \\log1$

On solving the function we got log1 and we know that the value of log 1 is zero, 0.

∴The required answer is zero, 0.

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