Math, asked by savithridevisimgai, 5 months ago

log2base10=0.3010,thenlog1by8base10​

Answers

Answered by RvP10
1

Answer:

 log_{10}( \frac{1}{8} )  =  - 0.9030

log_{10}( \frac{1}{8} ) = log_{10}(  {2}^{ - 3}  )

 =  - 3log_{10}( 2 )

 = -  3 \times 0.3010

 =  - 0.9030


savithridevisimgai: tq
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