Question

log2base4+log4 base4 + log x base 4+ log 16 base 4=6. Find x

Answer 1

log 2base 4= x
4^x=2
2^2x=2
1=2x
x=1/2 (do all logs in this way )

1/2+1+log x base4+1/2=6

2+log x base 4 =6
log x base 4=4
4^x=4
x=1



therefore the value of x is 1


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Answer 2

Hey there !!!!!!!!!!!!!!

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log₄2+log₄4+log₄x+log₄16=6

Using logₓa+logₓb=logₓab

log₄(2*4*x*16)=6

log₄(2*2²*2⁴*x)=6

log₄(2⁷*x)=6

   2⁷*x= 4⁶

   2⁷*x= (2²)⁶

    x=2¹²/2⁷

    x=2⁵

    x=32

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Hope this helped you................