Question

log2log3log5x=0,then x=​

Answer 1

Answer:

....

Explanation:

question is not proper.

Answer 2

In mathematics, before the discovery of numbers, many mathematical scholars used logarithms to change multiplication and division problems into addition and subtraction problems. In logarithms, power is raised to some number (usually the base number) to get another number. It is the inverse function of an exponential function. We know that mathematics and science constantly deal with large powers of numbers, the most important and useful ones being logarithms.

Logarithmic functions are inverses of exponential functions, and any exponential function can be expressed in logarithmic form. Logarithms are really useful because they allow us to work with very large numbers while also manipulating numbers of a much more manageable size.

If $x=2^{y}$ is to be solved for y in order to write it in functional form, a new word or symbol would have to be introduced. If $x=2^{y}$, then y = (power to base 2) is equal to x. To satisfy this need, the word logarithm, abbreviated log, is introduced.

Since we know that value  $log1$ is $0$

Hence if we put x as $1/5$ Then it will lead to the formation of the following function:

$log2log3log(5*1/5)\\log2log3log1=0$

Hence the value of x is  $1/5$

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