Question

Log2x+Log4x=6
find the value of x​

Answer 1

Answer:

16

Step-by-step explanation:

We can write  $log_4x$ as $\frac{1}{2}log_2x$ as $log_2x^{1/2}$

Now that the two logarathamic terms have the same base we can solve more easily

$log_2x + log_2x^{1/2}= 6$

$log_2(x*x^{1/2}) = 6$  (use the logarithm addition rule)

$x^{3/2} = 2^6$

$x = 2^{6*2/3}$

$x = 2^4 = 16$

Hope this helps

Answer 2

Answer:

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