Question

Log3(27) +{log48 - log6}÷log64

Answer 1

Answer:

7/2

Step-by-step explanation:

3 + 0.9/1.8 = 3 + 1/2 7/2

Answer 2

Answer: The value of Log3(27) +{log48 - log6}÷log64 is $\frac{7}{2}$.

Step-by-step explanation:

According to the question,

As given that

=Log3(27) +{log48 - log6}÷log64

=$\frac{log 27}{3} + [\frac{(log 48 - log 6)}{log 64} ]$

=$\frac{log (3)^{3} }{3} +[\frac{(log \frac{48}{6})}{log 64} ]$

=$\frac{3 log 3}{3} +[ \frac{log 8}{log8^{2} }]$

=$3+[\frac{log 8}{2 \times log 8} ]$

=3+$\frac{1}{2}$

=$\frac{6+1}{2}$

=$\frac{7}{2}$

Hence, the value of Log3(27) +{log48 - log6}÷log64 is $\frac{7}{2}$.

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