Question

log3(2x+1)-log3(x-7)=2​

Answer 1

Answer:

Step-by-step explanation:

$\log_3{ (2x+1 )}-\log_3 {(x-7)}=2\\\\\log_3 \frac {2x+1}{x-7}=2\\\\ \frac {2x+1}{x-7}=2^3=8\\\\8(x-7)=2x+1\\\\8x-56=2x+1\\\\6x=57\\\\\bf x=\frac{57}{6}= \frac{19}{2} =9.5$