Question

log3(2x-1)-log9(x² - 2) = 1/log2³
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Answer 1

Step-by-step explanation:

log3(2x-1) -log9 (x^2-2)=1/log^2

log6(2x-1)-log18 (x^2-2)= 1/log^2

log 7x-log 7x +-log18 +2x^2

1log^2 =log 27x^2

1log^2 -log18 =27x^2

1log = 27x^2

log ^1=27x^2/1log^1

log = 27x solution