Question

log3(3x-8)=2-x
please solve it it's urgent

Answer 1

hi friend,

the given question can also be written as ,by converting into exponential form,we get

3^x-8=3^(2-x)

→3^x-8=9/3^x

let 3^x be y

then

→y-8=9/y

→y²-8y-9=0

→y²-9y+y-9=0

→y(y-9)+1(y-9)=0

y =-1 and 9

but 3^x≠-1 since it should be positive

3^x=9

→3^x=3²

x=2


I hope this will help u :)

Answer 2

Answer:

Step-by-step explanation:

Just assume 3^x as y and then solve it simply .

U ll get a quadriatic equation and there is the solution.

This will work for next question too if u use prolipko.

Here u go.