Math, asked by netu87, 1 year ago

log3(x + 1) + log3(x + 3) = 1

netu87: nothing

Anonymous: Rascal mind your language:)). i know what u wana to wrote.

netu87: hat katya

Anonymous: Go and ask Ur Father.

netu87: tu puch angrej ki olad

netu87: katya

Anonymous: You must belong Hindu religion

netu87: yes

Anonymous: This is what character of Hindu people is

netu87: hat tum bohot ache ho jase

Answers

Answered by Anonymous

$HEYA \\ \\ \: log_{3}(x + 1) + log_{3}(x + 3) = 1 \\ \\ log_{3}((x + 1) \times (x + 3)) = log_{3}(3) \\ becoz \: \: log(m) + log(n) = log(m \times n) \\ \\ (x + 1) \times (x + 3) = 3 \\ \\ x {}^{2} + 3x + x + 3 = 3 \\ \\ x {}^{2} + 4x = 0 \\ \\ x(x + 4) = 0 \\ \\ x = 0 \: \: \: or \: \: \: \: (x + 4) = 0 \\ \\ x = 0 \: \: \: or \: \: x = - 4 \\ \\ x = - 4 \: \: will \: be \: rejected \: becoz \: domain \: \\ of \: log \: is \: set \: of \: positive \: real \: numbers \\ \\ therefore \: \: x = 0$

netu87: thanks

Answered by Anonymous

Step-by-step explanation:

$\begin{lgathered} log_{3}(x + 1) + log_{3}(x + 3) = 1 \\ \\ log_{3}((x + 1) \times (x + 3)) = log_{3}(3) \\ \\ Because \: \: log(m) + log(n) = log(m \times n) \\ \\ (x + 1) \times (x + 3) = 3 \\ \\ x {}^{2} + 3x + x + 3 = 3 \\ \\ x {}^{2} + 4x = 0 \\ \\ x(x + 4) = 0 \\ \\ x = 0 \: \: \: or \: \: \: \: (x + 4) = 0 \\ \\ x = 0 \: \: \: or \: \: x = - 4 \\ \\ x = - 4 \: \: \\ \\ Will \: Be \: Rejected \: Because \: Domain \: \\ Of \: log \: Is \: Set \: Of \: Positive \: Real \: Numbers \\ \\ Therefore \: \: \\ x = 0\end{lgathered}$

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log3(x + 1) + log3(x + 3) = 1​

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log3(x + 1) + log3(x + 3) = 1