Question

log32 base 9 Log 32 base 3
——————— / ———————— =
log25 base 1/5 Log 1/27 base 5

Answer 1

Answer:

loga base b= loga/logb

log(a)•^k base b= k*( loga/logb)

So , log5 base 3 = log5/log3

log 27 base 25= (log 27/log25)= (3*log 3)/(2* log 5)

So according to question

(log 5)/( log 3) *( 3/2)* ( log 3)/ (log 5 )

=3/2

Answer 2

as i have shown in the given solution, we use the formula log a to the base b = log a/ log b...