Question

log32 N = -3/5 the value of N is equal to
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Answer 1

Step-by-step explanation:

find the value of iflog 32 n =-3

Answer 2

The value of N = 1/8

Given :

$\displaystyle \sf{ log_{32}(N) = - \frac{3}{5} }$

To find :

The value of N

Solution :

Step 1 of 2 :

Write down the given equation

Here the given equation is

$\displaystyle \sf{ log_{32}(N) = - \frac{3}{5} }$

Step 2 of 2 :

Find the value of N

$\displaystyle \sf{ log_{32}(N) = - \frac{3}{5} }$

$\displaystyle \sf{ \implies N = {(32)}^{ - \frac{3}{5} } }$

$\displaystyle \sf{ \implies N = {( {2}^{5} )}^{ - \frac{3}{5} } }$

$\displaystyle \sf{ \implies N = {( {2}^{} )}^{ - \frac{3}{5} \times 5 } }$

$\displaystyle \sf{ \implies N = {( {2}^{} )}^{ - 3} }$

$\displaystyle \sf{ \implies N = \frac{1}{ {2}^{3} } }$

$\displaystyle \sf{ \implies N = \frac{1}{ 8 } }$

Hence the required value of N = 1/8

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