Log32x=-1/5 what is the process to find x
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log32(x)=15log32(x)=15
Rewrite log32(x)=15log32(x)=15 in exponential form using the definition of a logarithm. If xx and bb are positive real numbers and bb≠≠11, then logb(x)=ylogb(x)=y is equivalent to by=xby=x.
3215=x3215=x
Solve for xx
25(15)=x25(15)=x
Cancel the common factor of 55.
2=x2=x
Rewrite the equation as x=2x=2.
x=2
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