Question

Log32x=-1/5 what is the process to find x

Answer 1

answer

log32(x)=15log32(x)=15

Rewrite log32(x)=15log32(x)=15 in exponential form using the definition of a logarithm. If xx and bb are positive real numbers and bb≠≠11, then logb(x)=ylogb(x)=y is equivalent to by=xby=x.

3215=x3215=x

Solve for xx

25(15)=x25(15)=x

Cancel the common factor of 55.

2=x2=x

Rewrite the equation as x=2x=2.

x=2