Question

Log32x + log32(1/8)=1/5, then the value of x is equal to

Answer 1

Answer:10

Step-by-step explanation:

Answer 2

Answer:

We should find the value of $x$ using the given data and logarithm formula.

Answer: $x=16$

Step-by-step explanation:

From the given question,

          $\log_{32}x+\log_{32}\frac{1}{8}=\frac{1}{5}$

• On the left side base(32) are same in that two terms.
• Logarithm formula, $\log_{a}x+\log_{a}y=\log_{a}xy$
• So our given sum can be written as,

                $\log_{32}(x*\frac{1}{8})=\frac{1}{5}$

• Logarithm formula, $\log_{a}x=n$ ⇒ $x=a^ n$
• Now apply the above formula in the above equation.That is,

                           $x*\frac{1}{8} =(32)^ \frac{1}{5}$

• 32 can be written as, $2^5$.So that,

                           $x*\frac{1}{8} =(2^5)^ \frac{1}{5}$  

• Now cancel 5 in the power of 2.So that, we can get the following equation.

                          $x*\frac{1}{8} =2$  

                                $x=8*2$        

                                $x=16$  

• Final Answer: $x=16$