log36(1/216)....... yeh 36 base mein hai.........
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Hi ,
*************************************
we know that ,
i ) log a ( base a ) = 1
ii ) log mⁿ ( base a ) = n log m ( base a )
********************************************
Now ,
log (1/216 ) ( base 36 )
= log ( 1/6³ )( base 6² )
= log ( 6^-3 )( base 6² )
= ( -3 )/2 [ log 6 ( base 6 ) ]
= -3/2
I hope this helps you.
: )
*************************************
we know that ,
i ) log a ( base a ) = 1
ii ) log mⁿ ( base a ) = n log m ( base a )
********************************************
Now ,
log (1/216 ) ( base 36 )
= log ( 1/6³ )( base 6² )
= log ( 6^-3 )( base 6² )
= ( -3 )/2 [ log 6 ( base 6 ) ]
= -3/2
I hope this helps you.
: )
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