log36/25 3cube+3log2/9-log2 =2lpg16/25 how will i prove this question???
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Answered by
0
Answer:
first solve lhs and then rhs
use the law m log a = log a^m
Answered by
1
Answer:
=log{(36/25)^3 *(2/9)^3}-log2
=log {(36/25)^3 * (2/9)^3 *1/2}
=log {(6^2/5^2)^3 *(2/3^2)^3 *1/2}
=log{6^6/5^6 *2^3/3^6 * 1/2}
=log {6^6/5^6 *2^2/3^6}
=log{2^6*3^6/5^6 * 2^2/3^6}
=log{2^8/5^6}
=log{2^4/5^3}^2
=2log16/125
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