log4-1/2log25+3/4log16+3log5-1/2log64=2
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Answer:
Given,
L.H.S
log4-1/2log25+3/4log16+3log5-1/2log64
=> log(2)²-1/2log(5)²+3/4log(2)⁴+3log5-1/2log(8)²
=>2log2-1/2.(2)log5+3/4.(4)log2+3log5-1/2(2)log8
=>2log2-log5+3log2+3log5-log8
=> 5.log2+2.log5-log(2)³
=> 5.log2+2.log5-3log2
=> 2.log2+2.log5
=2log(2×5)
= 2.log(10)
= 2×1
= 2
R.H.S
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