Question

log4(2) + 7log4(3)- 2log4(5)
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Answer 1

Answer:

$5.84$

Step-by-step explanation:

log4(2)= log4 + log2 = 0.6020 + 0.3010= 0.9030

7 log4(3)=log4 + log3 = 0.6020+0.477=7(1.077)

2log 4(5)= log4 + log5 = 0.6020+0.6989=2(1.3010)=2.6020

log4(2) + 7log4(3)- 2log4(5)

0.9030+7.539-2.6020= 5.84

Answer 2

=0.6020+0.3010+7(0.6020+0.4771)-2(0.6020+0.6989)

=0.903+7.5537-2.6018

=5.8549

I hope you understand.