Question

log4+2log5+3log3+ 2log2​

Answer 1

no subtraction sign fr this question

Answer 2

HELLO MATE ! the solution for your question is evaluated by the formula

log m*n=log m + log n

Step-by-step explanation:

log6 +2log5+log4-log3-log2

⇒log2+log3 +2log5+log2+log2-log3 -log2 (simplifying into small parts)    

⇒ 2log2 + 2log5                                                                            

⇒2(log2+log5)                                                     (taking common)

⇒2(log2×5)

⇒2log10

⇒2×1                                                                     (∵  log10=1)      

⇒2