Question

log5(18-x^2)=log5(6-x)​

Answer 1

$\large \bold \green{ \underline{answer}} \\ x = - 3 \\ x = 4$

Step-by-step explanation:

$\large \bold{given} \\ log5 {}^{(18 - {x}^{2}) } = log(5) {}^{(6 - x)} \\ \large \bold \green{explanation} \\ if \: \: base \: \: are \: \: same \: \: then \: \: power \: \: will \: \: be \: \: equal \\ 18 - {x}^{2} = 6 - x \\ - {x}^{2} + x + 12 = 0 \\ - ( {x}^{2} - x - 12 )= 0 \\ {x}^{2} - x - 12 = 0 \\ {x}^{2} - 4x + 3x - 12 = 0 \\ x(x - 4) + 3(x - 4) = 0 \\ (x + 3)(x - 4) = 0 \\ x = - 3 \: \: and \: \: x = 4$