Question

log5 (x - 7) = 1 find x, if:​

Answer 1

Answer:

5(x-7) = 1

5x - 35 = 1

5x = 1 +35

5x = 36

x = 36/5

Answer 2

Answer:

hello

Step-by-step explanation:

its will be as follows,,,

log_7 ( {2}^{x} - 1) + log_{7}( {2}^{x} - 7 ) = 1log

7

(2

x

−1)+log

7

(2

x

−7)=1

log_{7}(( {2}^{x} - 1) ( {2}^{x} - 7)) = 1log

7

((2

x

−1)(2

x

−7))=1

By defination,

{2}^{2x} - 8. {2}^{x} + 7 = {7}^{1}2

2x

−8.2

x

+7=7

1

{2}^{2x} - {2}^{3} . {2}^{x} = 02

2x

−2

3

.2

x

=0

{2}^{2x} - {2}^{3 + x} = 02

2x

−2

3+x

=0

{2}^{2x} = {2}^{3 + x}2

2x

=2

3+x

As the bases are same the indices will be same ,

2x = 3 + x2x=3+x

x = 3x=3

Hope it helped you

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