log5(x2 - 19 = 3 please give the answer of this question
Answers
Answered by
5
Answer:
x = ± 12
Note:
★ If log_a(N) = n , then N = aⁿ
★ log(AB) = logA + logB
★ log(A/B) = logA - logB
★ log(Nⁿ) = n×(logN)
Solution:
We know that ;
If log_a(N) = n
then N = aⁿ
Thus,
log_5(x² - 19) = 3
=> x² - 19 = 5³
=> x² = 5³ + 19
=> x² = 125 + 19
=> x² = 144
=> x = √144
=> x = ± 12
Hence,
x = ± 12 .
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Answered by
0
Answer:
your answer is + 12
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