Question

log6 1 + log6 216/ log6 36

Answer 1

0+3/2log6 6
3/2 is answer

Answer 2

The value of $x=\dfrac{3}{2}$.

Step-by-step explanation:

We have,

$\log _61+\dfrac{\log _6216}{\log _636} =x$

To find, the value of x = ?

∴ $\log _61+\dfrac{\log _6216}{\log _636} =x$

⇒ $\log _66^{0} +\dfrac{\log _66^{3} }{\log _66^{2} } =x$

⇒ $0\times \log _66+\dfrac{3\times \log _66}{2\times \log _66} =x$

[ ∵ $\log a^{m} =m\log a$]

⇒ $0\times 1+\dfrac{3\times 1}{2\times 1} =x$

[ ∵ $\log_aa =1$]

⇒ $0+\dfrac{3}{2} =x$

⇒ $\dfrac{3}{2} =x$

∴ $x=\dfrac{3}{2}$

Hence, the value of $x=\dfrac{3}{2}$.