Question

log6^(x-2)(x+3)=1


pls solve this and attempt to solve only if you know how to solve​

Answer 1

Answer:

1

Step-by-step explanation:

$log6(x - 2)(x + 3) = 1 \\ log6x(x - 2) + 3(x - 2) = 1 \\ log6x {x }^ {2} - 2x + 3x - 6 = 1 \\ log6x - 6 = 1 \\ log6 = 6 \\ log = 6 \div 6 \\ log = 1$