Math, asked by meghamukundajana, 2 days ago

log7^1/7 find the value​

Answers

Answered by LaeeqAhmed
1

 log_{7}( \frac{1}{7} )

 \implies log_{7}(  {7}^{ - 1}  )

 \purple{ \sf since : }

 \red{ \boxed{  log( {a}^{m} )  = m log(a) }}

\implies( - 1) \times log_{7}( 7)

\red{ \boxed{  log_{a}(a)  = 1}}

 \implies ( - 1) \times 1

 \orange{ \therefore  log_{7}( \frac{1}{7} ) =  - 1 }

Answered by anandchandanshive65
1

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