Question

log7 (2)=m then log49 (28)=?

Answer 1

If log72=m
log
7
⁡
2
=
m
then log4928
log
49
⁡
28
is equal to

2(1+2m)1+2m221+2m1+m 2(1+2m)
1
+
2
m
2
2
1
+
2
m
1+m
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A)
Given log72=m
log
7
⁡
2
=
m
Now log4928=log28log49
log
49
⁡
28
=
log
⁡
28
log
⁡
49
=>log72log7+log42log7
=>
log
⁡
7
2
log
⁡
7
+
log
⁡
4
2
log
⁡
7
=>12
=>
1
2
log72
log
7
⁡
2
=>12
=>
1
2
+m
+
m
=>1+2m2