Question

log7√7 + log3√3 - log5√5/log4.2​

Answer 1

Answer:

           3/2

Step-by-step explanation:

$\displaystyle\frac{\log7\sqrt7+\log3\sqrt3-\log5\sqrt5}{\log 4.2}\\\\=\frac{\log7^{3/2}+\log3^{3/2}-\log5^{3/2}}{\log\tfrac{42}{10}}\\\\=\frac{\tfrac32\log7+\tfrac32\log3-\tfrac32\log5}{\log\tfrac{21}5}\\\\=\frac{\tfrac32(\log7+\log3-\log5)}{\log\tfrac{21}5}\\\\=\frac{\tfrac32\log\tfrac{7\times3}{5}}{\log\tfrac{21}5}\\\\=\frac{\tfrac32\log\tfrac{21}5}{\log\tfrac{21}5}\\\\=\tfrac32$

Answer 2

Answer:

log(7√7×3√3)÷(5√5-4.2)