log7 log5(√x^2 +5 +x)= 0 find x
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Answer:1/2log72 or 4
Step-by-step explanation:
=log 7 log 5 ((√x)^2+5+x)=0
=log 7 log 5( x+5+x)
=log 7+ log 5(2x+5)
=log 12(2x+5)
That is,
2x log 12* log 60
That is,
2x log 12 +log 60
That is,
2x log 72
===1/log 72=2x
===1/2 log 72=x
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