Math, asked by ninad160, 1 year ago

log7 log5(√x^2 +5 +x)= 0 find x

Answers

Answered by 948617ss
0

Answer:1/2log72 or 4

Step-by-step explanation:

=log 7 log 5 ((√x)^2+5+x)=0

=log 7 log 5( x+5+x)

=log 7+ log 5(2x+5)

=log 12(2x+5)

That is,

2x log 12* log 60

That is,

2x log 12 +log 60

That is,

2x log 72

===1/log 72=2x

===1/2 log 72=x

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